Question

A solid of length 12 cm is immersed 9 cm in water. The density of solid is

Answer 1

Answer:

Let V= volume of the rod and V

in

= volume of rod immersed in liquid

For equilibrium:

Weight of rod = Buoyant force by liquid on rod

By Archimedes' law, Buoyant force = weight of liquid displaced

⇒Vdg=V

in

(2d)g

⇒V

in

=

2

V

So 50% of the rod is immersed in the liquid

Explanation:

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