A solid rectangular piece of iron measures 1.05 m X 70 cm X 1.5 cm. 1 cm3 of iron weighs
8 grams. Find the weight of this piece in kilograms?
Answers
Answered by
12
here is a complete and simple solution to your answer buddy:
L = 1.05 m= 105 cm
B= 70 cm
H= 1.5 cm
therefore, Vol = 105 * 70 * 1.5 = 11025 cm3
The weight of 1 cm3 of iron plate is 8 gram
Therefore, the weight of 11025 cm3 of iron plate is = 11025 * 8 = 88200 grams.
weight in Kg = 88200/1000 = 88.2 kg.
Answered by
5
volume of solid rectangular piece of iron=lbh
=1.05×1.5×70
=740.25cm^3
1cm^3=8g=0.008kg
740.25cm^3=740.25×0.008
=5.922kilo gram
Similar questions