a solid sphere of radius 6 cm is melted into a hollow cylinder of uniform thickness. if the external radius of the base of the cylinder is 5 cm and it's height 32 cm find its uniform thickness of the cylinder
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Hey there,
The radius of the solid sphere = 6cm
The outer radius of the cylinder formed =4cm
The height of the cylinder =72cm
Let the internal radius be x cm
So, Volume of sphere =Volume of cylinder formed
4/3*22/7*6*6*6=22/7*(R^2-r^2)*72
4/3*216=(16-r^2)*72
4=(16-r^2)
r^2=16-4
r^2=12
r = 3.46cm
The uniform thickness is R-r 4-3.46= 0.54cm 0.
Hope this helps!
The radius of the solid sphere = 6cm
The outer radius of the cylinder formed =4cm
The height of the cylinder =72cm
Let the internal radius be x cm
So, Volume of sphere =Volume of cylinder formed
4/3*22/7*6*6*6=22/7*(R^2-r^2)*72
4/3*216=(16-r^2)*72
4=(16-r^2)
r^2=16-4
r^2=12
r = 3.46cm
The uniform thickness is R-r 4-3.46= 0.54cm 0.
Hope this helps!
yogita14:
your smartness works
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