Physics, asked by nishahjp00077, 11 months ago

a solid weighs 15g in air and 13g when completly immersed in liquid. find relative density and volume.

Answers

Answered by ankixx55
0

Answer:

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Explanation:

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Answered by dhruvpatil199
1

Answer:

Given, weight of solid in air = 30 gf and weight of solid in liquid = 26 gf., R.D of liquid = 0.8

Therefore, Density of liquid = 0.8 g cm-3

(i) Let V be the volume of the solid.

Weight of liquid displaced = Volume of liquid displaced xdensity of liquid x g

= V 0.8g dyne

= V 0.8 gf

Loss in the weight of the solid when immersed in the liquid = 30 - 26 = 4gf

But the weight of liquid displaced is equal to the loss in weight of the solid when immersed in liquid.

Therefore, Vx0.8 = 4 or V = = 5 .

(ii) Given, weight of solid = 30gf

Therefore, Mass of solid = 30 g

Density of solid =

Hence relative density of solid = 6

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