Question

A solution contains 20gm of sugar in 300 gm ofwater. calculate the concentration in terms of mass by mass percentage of the solution​

Answer 1

Answer:

the concentration of this sugar solution is 20 % ( by Mass )

Step-by-step explanation:

According to the question,

Mass of solute  ( sugar )  = 20 g

Mass of solvent ( water )  = 80 g

Mass of the solution = Mass of solute + Mass of solvent = 36 + 100 = 136 g

We know,

Concentration of solution =  

Mass of solute / (Mass of solute + Mass of solvent) X 100

= {20 / ( 20+80 )} X 100

= (20 / 100) x 100

= 20 %

Thus, the concentration of this sugar solution is 20 % ( by Mass )

Answer 2

Answer:

6.67% is the concentration of the sugar solution by mass.

Step-by-step explanation:

Given:-

Total mass of solution = 300 gm

Mass of sugar (Solute) = 20 gm

Mass of water (Solvent) = Mass of solution - Mass of sugar

                                       = 300 - 20

                                       = 280 gm

To find:-

The concentration in terms of mass by mass percentage of the solution.

Step 1 of 1

As we know,​

Concentration of sugar solution = (Mass of solute)/(Mass of solution)

                                                      = 20/300

                                                      = 1/15  gm

Now,

The percentage of the concentration of the sugar solution is,

= $\frac{1}{15}\times 100$

= 20/3

= 6.67% (Approx.)

Therefore, 6.67% is the concentration of the sugar solution by mass.

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