Chemistry, asked by sruti2678, 10 months ago


A solution is prepared by dissolving 15g of cane sugar in 60 g of water. Compute the mass
percentage of sugar in the solution
A.80 B.25 C.75 D.20

Answers

Answered by rinkimalik
4

Mass of sugar = 15g

Mass of water = 60g

Solution = Solvent + Solute

15+60=75g

% of sugar =

\frac{15}{75} \times 100 = 20\%

% of water =

\frac{60}{75} \times 100 = 80\%

Hope it helps you

Thanks for asking....

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@ Prabhudutt

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THANKS

1

Comments Report

HEY Buddy.....!! here is ur answer

Given that : A solution is prepared by dissolving 15g of sugar and 60g of water then mass of the solution = 60+15 = 75g

Now, percentage of sugar in solution = 15×100/75

=> 20%

And percentage of water in solution = 60×100/75

=> 80%

I hope it will be helpful for you....!!

Answered by bunnyroll
2

Explanation:

total mass =mass of sugar cane + mass of water

=15g +60g

=75g

............

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