Physics, asked by ayushkumar2186, 11 months ago

A source of sound S and detector D are placed at some distance from one another. a big cardboard is placed near hte detector and perpendicular to the line SD as shown in figure. It is gradually moved away and it is found that the intensity changes from a maximum to a minimum as the board is moved through a distance of 20 cm. Find the frequency of the sound emitted. Velocity of sound in air is 336 m s−1.

Answers

Answered by vikasviki24497
1

Answer:

a sound is a volume of a sound pollution and noise pollution and water pollution is this is the money of pollution I don't know this answer please give me one or two weeks I will tell the velocity I will tell 36 metre per second thank you I hope you are giving my time

Answered by shilpa85475
0

The frequency of the sound emitted is 420 HZ

Explanation:

Step 1:

Given data,  

V = 336 m/s  

V is The velocity of sound in air

λ/4 = distance between maximum and minimum intensity  

λ/4 = 20 cm  

λ = 80 cm

Step 2:

Converting centimeter to meter ( divide 100 )

λ = 80/100 m  

λ = 0.8 m  

Step 3:

We know that  

n = frequency = v/λ  

frequency = 336/(0.8)  

frequency = 420 HZ  

420 HZ The sound frequency it released

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