a sphere immersed in an incompressible fluid expands according to a given law r = r(t). determine the fluid pressure at the surface of the sphere
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Pressure at a depth h below the surface of water=atmospheric pressure + pressure due to water column of height h.If atmospheric pressure is P, then 2P=P + hρg or hρg = PBut P=10 N cm–2=l0N/(10–2 m)2=105 N m–2Hence h=P/ρg=105/(103 × 9.8)=10.2 mThus a water column of height 10.2 m exerts a pressure equal to the atmospheric pressure.
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