A sphere of diameter 6 cm is dropped into a cylindrical vessel, partly filled with water, whose diameter is 12cm. IF the sphere is completely submerged in water, by how much will the surface ofwater de raused in the cylindrical vessel?
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Volume of water raised will be equal to the volume of sphere
(let R be the radius of cylinder and r be the radius of sphere, H be the height of the water raised)
π * R square * H = (4/3) * π * r raise to power 3
π * 6 square * H = (4/3) * π * 3 raise to power 3
If we solve the above equations we get H = 1 cm
So water will be raised to 1 cm
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