Question

A sphere of mass 1 kg is moving with a
velocity4i - 1. It hits a wall and rebounds
with velocity
i+3j. The coefficient of
restitution between the sphere and the wall
is
​

Answer 1

Answer:

9/16

Explanation:

final momentum=m(i+3j)

initial momentum=m(4i-j)

impulse=change in momentum=m(i+3j)-m(4i-j)=m(-3i+4j)

component of the initial velocity along impulse u=(4i-j).(-3i+4j)/√9+16=-16/5

component of final velocity along impulse v=(i+3j).(-3i+4j)/√9+16=9/5

v/u=9/5/16/5=9/16