Question

A sphere of mass 10 g has net charge of = -2.5* 10^9 C
find the number of excess electrons on the sphere?
what do we mean by excess electrons here..pls explain

Answer 1

Answer:

$excess \: electrons = 1.56 \times {10}^{28} \:$

Explanation:

$q = ne \\ n = \frac{q}{e} \\ n = \frac{ - 2.5 \times {10}^{9} }{1.6 \times {10}^{ - 19} } \\ n = - 1.56 \times {10}^{28} \\ \\ excess \: electrons</strong><strong>\</strong><strong>:</strong><strong> </strong><strong>are \: those \: electrons \: which \: \\ are \: not \: of \: its \: own \: body \: they \: get \: in \: that \: \\ body \: through \: other \: sources \: by \: charging \: etc$

Hope this answer is helpful.