Question

A sphere of radius 5 cm has a charge of 31.41 microcoulomb calculate the surface density of charge ​

Answer 1

Answer:

Hope you will understand

10.0031847×10^-4 c/m^2

Answer 2

$\huge\red{\underline{{\boxed{\textbf{QUESTION}}}}}$

A sphere of radius 5 cm has a charge of 31.41 microcoulomb calculate the surface density of charge ?

$\huge\red{\underline{{\boxed{\textbf{ANSWER}}}}}$

The surface density of charge of the sphere is 999.8 C/ m².

The radius of sphere ( r ) = 5 cm

                                                  = 5x10⁻² m

Thus, Area ( a ) = 314.16x10⁻⁴ m²

Charge of sphere ( q ) = 31.41 micro Coulomb

                                             = 31.41 x 10⁻⁶ C

Therefore, The surface density of charge = q / a

                                                      = 31.41 x 10⁻⁶ C/ 314.16x10⁻⁴ m²

                                                      = 999.8 C/ m²

__________________

@HarshPratapSingh