Question

A spherical glass vessel has a cylindrical neck 8 cm long, 2 cm in diameter, the diameter of the spherical part is 8.5 cm. Find the volume of water it can hold. (use π = 3.14)

Answer 1

Answer:

see below

Step-by-step explanation:

incase of cylinder

h=8cm

d=2,r=1

volume of cylinder πr^2

3.14×1×1= 3.14

in case of sphere d=8.5cm

r=8.5/2

volume of sphere 4/3πr^3

4÷3×3.14×8.5÷2×8.5÷2×8.5÷2=321.392083

no volume of cylinder +volume of sphere

3.14+321.392083

324.532083cm3

1cm3=1000l

324.532083÷1000

Answer 2

$\textrm{Volume of vessel = Volume of sphere + Volume of cylinder}$

$\longrightarrow\rm{Volume\: of\: vessel = 4/3\pi r^3+ \pi r^2h=[4/3\times\pi\times r^3]+ [\pi \times r^2\times h]}$

$\longrightarrow\rm{Volume\: of\: vessel=[4/3\times 3.14\times r^3]+ [3.14\times r^2\times h]}$

$\longrightarrow\rm{Volume\: of\: vessel=[4/3\times 3.14\times (Diameter/2)^3]+ [3.14\times (Diameter/2)^2\times h]}$

$\longrightarrow\rm{Volume\: of\: vessel=[4/3\times 3.14\times (8.5/2)^3\:cm^3]+ [3.14\times (2/2)^2\:cm^2\times h]}$

$\longrightarrow\rm{Volume\: of\: vessel=[4/3\times 3.14\times (4.25)^3\:cm^3]+ [3.14\times (1)^2\:cm^2\times h]}$

$\longrightarrow\rm{Volume\: of\: vessel=[4/3\times 3.14\times (4.25)^3\:cm^3]+ [3.14\:cm^2\times h]}$

$\longrightarrow\rm{Volume\: of\: vessel=321.39\:cm^3+ [3.14\:cm^2\times 8\:cm]}$

$\longrightarrow\rm{Volume\: of\: vessel=321.39\:cm^3+25.12\:cm^3=346.51\:cm^3}$

$\boxed{\textrm{Hence we can say that, The child is not correct}}$