Science, asked by cakash4725, 9 months ago

A spring constant is 4 x 103 N/m. How much work will be done to compress the spring to 0.04 m?

Answers

Answered by apoorv10dbms2020
3

Answer:

Work done=Elastic Potential Energy

 =  \frac{1}{2} k {x}^{2}  \\  =  \frac{1}{2}  \times 4 \times  {10}^{3}  \times  {(0.04)}^{2}  \\  = 3.2 \: joule

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