Question

A spring stores 1 j of energy for a compression of 1 mm.The additional work to.Be done.To compress it further by 1mm

Answer 1

1j                                                             is the answer because we know we have use 1j to compress 1mm

Answer 2

Answer:

3j

Explanation:

Initial case w=1/2kx^2= 1 (given)

Final case w = 1/2k *2^2= 4 j

Change = final _initial

               = 4_1= 3j

Hope it helps