Question

A train travelling at a speed of 60 km/hr catches another train travelling in the same direction and then leaves it 120m behind in 18 seconds. The speed of the second train is?

Answer 1

$\textbf{\huge{ANSWER:}}$

Let the speed of the second train be = x

Converting 60 km/hr into m/s:

$\frac{60 \times 1000}{3600} = \frac{50}{3} \: m {s}^{ - 1}$

Now, As both the trains are travelling in the same direction, their relative distance will be:

$\frac{50}{3} - x = \frac{120}{18} \\ \\ = > \frac{50 - 3x}{3} = \frac{120}{18} \\ \\ = > 900 - 54x = 360 \\ \\ = > 540 = 54x \\ \\ = > 10 = x$


Converting it into km/hr:

$10 \times \frac{3600}{1000} = 36$
$\textbf{\huge{36 km/hr}}$ ans.

Hope it Helps!! :)

Answer 2

hey there !! .


the speed of the second train is 36km/hr.

solution told in attachment ..

hope it helps !!

all the best ,,