Question

a sprinter ina 100m race, cover4meter in frist second , 30 m in next 4 second, 30m in next 4second and 52m in another 4second and finish for the race10second
(1) calculate the average velocity of spinter
(2) in which time intervel is the average velocity attattaind by the spinter maximum? state this velocity in appropriate unit​

Answer 1

Answer:

begin mathsize 12px style left parenthesis straight i right parenthesis space Average space velocity space equals space fraction numerator Total space distance space travelled space over denominator Total space time space taken end fraction space

rightwards arrow space Average space velocity space equals space fraction numerator 100 space straight m over denominator 10 space straight s end fraction space equals space 10 space straight m divided by straight s space end style

 

(ii)  For all the time intervals we need to calculate the initial velocity, acceleration, displacement and the final velocity

Formulas used:

s = ut + (1/2)at2 and v = u + at

 

Time s 0 1 5 9 10

Distance m 0 4 34 86 100

Velocity m/s 0 8 7 19 9

 

So, peak velocity attained by the is 19 m/s at the end of the 9th second.

 

(iii) Acceleration is highest between 5th to 9th second. It is 3 m/s2

Explanation: