sum of the digits of a two-digit no. is 9. when we interchange the digits, it is found that the resulting new number is greater than the original no. by 27. what is the two-digit no. ?
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Let the first number (ones digit) = x
Let the first number (tens digit) = 9 - x
Therefore, according to the question,
x * 10 + 9 - x
After interchanging
10(9 - x) + x
By equating them;
10x + 9 - x - 27 = 90 - 10x + x
9x - 18 = 90 - 9x
9x + 9x = 90 + 18
18x = 108
x = 6
9 - x = 9 - 6 = 3
Therefore, the number = 36
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