Question

a square hole of cross section area 4 cm square is drilled across a cube with its length parallel to a side of the cube if an edge of the cube measures 5 cm, what is the total surface area of the body so formed

Answer 1

So surface area of cube of side x is $6x^2$
But we are drilling a hole inside cube 
The hole drilled is a cuboid with dimensions 4x4x5
Surface area formed inside cube is combination surface area of 4 four faces
parallel to faces of cube
Area of rectangle is $length*breadth$
which is 20
So four all faces in total is 80
but since a hole is drilled 2 faces have reduction in surface area in cube
So total is
Surface area of cube + surface area of 4 faces parallel to faces of cube - surface area of top and bottom of square
$= 6(5)(5) + 4(4)(5) - 2(4)(4) = 198$

Answer 2

Answer:

Step-by-step explanation:

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