Question

(a square minus b upon 2 ) whole square .........pls solve with the formulae a and b

Answer 1

Answer:

((a^2 - b) /2)^2

= (a^2-b) ^2/4

= (a^2)^2 + b^2 - 2a^2b /4. (using (x - y) ^2 = x^2 + y^2 - 2xy)

= (a^4 + b^2 - 2a^2b)/4