A squax of a paper of side 12 cm is rolled as a cylinder. Find the curved surface area of cylinder.
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Side of a square = 12
Now, when this square paper is rolled to form a cylinder
Height = 12 cm
Now, let the base radius be r.
So,
Side of a square=circumference of the base of the cylinder
12=2πr
r=12/2π
r=6π
Next, we know that the curved surface area of the cylinder is given by;
CSA=2πrh
CSA=2π(6/π) 12
CSA=144
Therefore, the curved surface area of the cylinder is given by 144 cm^2
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Now, when this square paper is rolled to form a cylinder
Height = 12 cm
Now, let the base radius be r.
So,
Side of a square=circumference of the base of the cylinder
12=2πr
r=12/2π
r=6π
Next, we know that the curved surface area of the cylinder is given by;
CSA=2πrh
CSA=2π(6/π) 12
CSA=144
Therefore, the curved surface area of the cylinder is given by 144 cm^2
plzz mark as brainliest answer !!!
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