A steel rod of diameter 1 cm is clamped firmly at each end when its temperature is25 degree c so that it cannot contract on cooling the tension in the rod at 0 degree c is approximately
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Explanation:
Given A steel rod of diameter 1 cm is clamped firmly at each end when its temperature is 25 degree c so that it cannot contract on cooling the tension in the rod at 0 degree c is approximately
- Given diameter = 1 cm = 10^-2 m
- Change in temperature is ΔT = 25 – 0
- = 25
- Now young’s modulus Y = stress / strain
- Stress = y x strain
- Now alpha coefficient of linear expansion
- Strain = change in length / original length
- = Δ l / l
- = α Δ θ
- Now stress = Y α Δ θ
- We know that stress = force / unit area
- So Tension = Y A α Δ θ
- = Y π d^2 / 4 α Δ θ
- = 2 x 10^11 x 3.14 x 10^-4 x 10^-5 x 25 / 4
- = 3925 N
≅ 4000 N
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