Question

A stone dropped from a height h reaches at earth surface in 1 sec . if the same stone taken to moon and drop freely from height h then it will reaches at the surface of moon in the time

Answer 1

We have,

S=ut+a(t squared)/2

On earth S=h

U=0

T=1sec

a=10m/s2

h=0(1)+10(1 square)/2

h=5 metres

On moon acceleration=1/6 of acceleration on earth

A=10/6

S=h=5m

U= 0

t=?

S=ut+at2/2

5=0+(10/6)*(t squared)÷2

1=t squared/6

=>t squared=6

=>[t=square root of 6]

Answer 2

Answer:

s = ut+1/2at²

h= 0 (1) + 1/2× 10×1

h =5

A = 10/6

S = h= 5m

u = 0

t = ?

s = it + 1/2 at²

5 = 0 + 1/2 × 10/6 × t²

1 = t²/6

t = square root of 6

therefore, root of 6 sec