Question

a stone falls from a building and reaches at the ground 2.5 second lafter. how it is the building (g= 9.8m/s^2)

Answer 1

Hey MATE!

We are given that g = 9.8m/s²

t = 2.5s

u = 0m/s

We can apply 2nd equation of motion here:

s = ut + 1/2 at²

h = ut + 1/2 gt²

h =
$0(2.5) + \frac{1}{2} \times 9.8 \times 2.5 \times 2.5$
h = 0 + 4.9 × 6.25

h = 30.625 m Answer.

Hope it helps

Hakuna Matata :))