A stone falls from a height of 19.6m .how long it takes to reach on earth
Answers
Answered by
2
Given that:
d= 19.6m
The acceleration must be due to gravity which equals 9.8m/s^2
When a body is falles frellely from height then it's initial velocity equals 0m/s
Using the third equation of motion we will first find the final velocity
2as =v^2 -u^2
2 (19.6)(9.8) = v^2 -0
384.16 = v^2
Then v (final velocity)= root 384.16
= 19.6
Now, to find the time taken by the body equal
a=(v-u)/t
9.8 = (19.6 -0)/t
9.8t= 19.6
t = 19.6/9.8
t = 2
So, the time taken by body to reache the earth is 2 s.
d= 19.6m
The acceleration must be due to gravity which equals 9.8m/s^2
When a body is falles frellely from height then it's initial velocity equals 0m/s
Using the third equation of motion we will first find the final velocity
2as =v^2 -u^2
2 (19.6)(9.8) = v^2 -0
384.16 = v^2
Then v (final velocity)= root 384.16
= 19.6
Now, to find the time taken by the body equal
a=(v-u)/t
9.8 = (19.6 -0)/t
9.8t= 19.6
t = 19.6/9.8
t = 2
So, the time taken by body to reache the earth is 2 s.
Similar questions