a stone is dropped down a deep well from rest the well is 50 metre deep how long will it take to reach the bottom of the well given a equal to 9.8 metre second -2
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Answer:
Explanation:
ou only need to plug it into the formula for distance d expressed as a function of acceleration a and time t:
d=1/2at2
Here d=50 and a=9.8
Therefore 50=1/2*9.8*t^2=4.9 t^2
t^2=50/4.9=10.20408
(50/4.9) and you get t= 3.19 sec., or 3.2 sec. to the nearest decimal
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