Physics, asked by 777, 1 year ago

A stone is dropped freely from a tower .it takes4seconds to reach ground ,what is the height of the tower (g:10)?

Answers

Answered by Anonymous
5
s = ut + 1/2at²
so here initial velocity (u) = 0
acceleration(a) = acceleration due to  gravity(g) = 10 m/s²
time (t)= 4 s
so 
s = 0×4 + 1/2 ×10 × 4²
s = 80 m 
so the height of the tower is 80  m

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Answered by jamunajohn88
1
u=0    t=4s   a=g=10m/s2 s=ut+1/2gt2     ie    s =o x4+1/2 x10 x4 x4=0+ 1/2 x160=80m
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