A stone is dropped freely from a tower .it takes4seconds to reach ground ,what is the height of the tower (g:10)?
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5
s = ut + 1/2at²
so here initial velocity (u) = 0
acceleration(a) = acceleration due to gravity(g) = 10 m/s²
time (t)= 4 s
so
s = 0×4 + 1/2 ×10 × 4²
s = 80 m
so the height of the tower is 80 m
so here initial velocity (u) = 0
acceleration(a) = acceleration due to gravity(g) = 10 m/s²
time (t)= 4 s
so
s = 0×4 + 1/2 ×10 × 4²
s = 80 m
so the height of the tower is 80 m
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u=0 t=4s a=g=10m/s2 s=ut+1/2gt2 ie s =o x4+1/2 x10 x4 x4=0+ 1/2 x160=80m
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