Question

A stone is dropped from a cliff 100m what will be it's final velocity before touching the ground

Answer 1

Answer:-

As the stone is dropped from a cliff the following points are necessary:-

u = 0.

h = 100m.

a =g.

Here body will fall under influence of gravity so acceleration due to gravity should be considered.

Explanation:-

From third law of motion

${v}^{2} - { u}^{2} = 2as$

substituting the values.

${v}^{2} - 0 = 2 \times 9.8\times 100$

${v}^{2} = 1960$

$v = \sqrt{1960}$

$v = 14 \sqrt{10}$

or

$14 \times 3.16$

$v = 44.24$

so,the final velocity before touching the ground is 44.24 m/s or

$14 \sqrt{10} \frac{m}{s}$