A stone is dropped from the roof of a building . It takes 4 seconds to reach the ground . Find the height of the building . (Take g = 9.8 m/s^2)
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h = 1/2gt²
h = 1/2 × 9.8 × 4
h = 19.6 m
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Answer:
Given,
Initial velocity = u = 0
time taken = t = 4s
acceleration = g = 9.8 m/s²
Using 2nd equation of motion we get,
x=ut+1/2at²
=(0) (4) + (1/2) (9.8) (4) (4)
= 78.4m
So, the height of the building is 78.4 m.
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