Question

A stone is dropped from the top of a tower of height 125 m. The distance tracelled by it during last second of its fall is (g=10ms-2)

Answer 1

45 is the answer

mark it the brianliest

Answer 2

u=0m/s
a=10m/s^2
S=125 m
S=ut+1/2 at^2
125=0×t +1/2×10tsquare
125=5tsquare
125/5=tsquare
25=tsquare
root25= 5 secs
t= 5secs

Dist. travelled in 5 secs= 125m
Dist. travelled in 4 secs=
S=ut +1/2 atsquare ( in place of t=4 )
125= 0×4+1/2×10(4)square
125=5×16
125=80
125-80=0
=45m
So dist. travelled in last 1 sec is 45 m ( Ans )