An object is dropped from height of 120m.The acceleration of the object is 10ms-2 downwards. Find the distance travelled and velocity after 3 sec.
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hey here is your answer
Using,
S = ut + ½ gt2
=> S = (0)(3) + (0.5)(10)(32)
=> S = 45 m
This is the distance traveled in 3 s.
Velocity after 3 s is, v = u + gt
=> v = 0 + (10)(3)
=> v = 30 m/s
hope it helps you
Please mark as BRAINLIEST
Using,
S = ut + ½ gt2
=> S = (0)(3) + (0.5)(10)(32)
=> S = 45 m
This is the distance traveled in 3 s.
Velocity after 3 s is, v = u + gt
=> v = 0 + (10)(3)
=> v = 30 m/s
hope it helps you
Please mark as BRAINLIEST
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