A stone is dropped from.The top of tall cliff and n second later another stone is thrown vertically downwards with a velocity u.Then the second stone overtakes the first below the top of the cliff at a distance given by
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The equation for an object in freefall is h(t)=g/2 t²+vt+c. In this case, we can ignore c, because both stones are being released from the same height. Let t be the time at which the first stone is released, and t-1 be the time the second one is thrown. Then they meet at:
g/2t²=g/2(t-1)²+v(t-1)
The equation for an object in freefall is h(t)=g/2 t²+vt+c. In this case, we can ignore c, because both stones are being released from the same height. Let t be the time at which the first stone is released, and t-1 be the time the second one is thrown. Then they meet at:
g/2t²=g/2(t-1)²+v(t-1)
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