Question

a stone is dropped into a 10m deep well. after how many second of dropping the stone the sound of splash would he heard? given g=10m per second square. velocity of sound in air = 340m per second

Answer 1

depth of well=10m

Time required to produce sound by splashing inside well...
use equation of motion-

$s = ut + \frac{1}{2} g {t}^{2} \\ 10 = 0 + \frac{1}{2} \times 10 {t}^{2} \\ t = \sqrt{2} sec.$
Now time taken by sound to reach our ear will be-

$time = \frac{distance}{speed} \\ = \frac{10}{340} = \frac{1}{34} = 0.029s$
Total time required to hear splash sound after dropping stone is-

=√2+0.029s

=1.479 seconds.

Hope it will help you‼️

Answer 2

1+1/34= 1+.03 nearly 1.03