A stone is thrown horizontally outward from the top of a bridge. The stone is released 10.6 m above the
street. The initial velocity of stone is 5 m/s determine (a) total time that stone is in air (b) magnitude and
direction of the velocity of the projectile just before it strikes the street.
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Answer:
Vertical component of initial velocity is u×sinθ= 25×
2
1
Time taken is 2.5 seconds
Height is u×t+
2
1
×a×t×t
H=25×
2
1
×2.5+
2
1
×9.8×2.5×2.5=61.875 m
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