Physics, asked by khushikot, 4 months ago

A stone is thrown horizontally outward from the top of a bridge. The stone is released 10.6 m above the
street. The initial velocity of stone is 5 m/s determine (a) total time that stone is in air (b) magnitude and
direction of the velocity of the projectile just before it strikes the street.​

Answers

Answered by btsarmy6393
1

Answer:

Vertical component of initial velocity is u×sinθ= 25×

2

1

Time taken is 2.5 seconds

Height is u×t+

2

1

×a×t×t

H=25×

2

1

×2.5+

2

1

×9.8×2.5×2.5=61.875 m

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