Question

a stone is thrown in a vertically upward direction with a velocity of 5 metre per second if the acceleration of the stone during the motion is 10 M per second square in the downward Direction What will be the height attained by the store and how much time will it take to reach there

Answer 1

Since the stone is thrown vertically upwards...
So,
v(final velocity)=0. , u (initial velocity)=5 m/s
acceleration upwards = -g = -10 m/sec^2
Now,
Height attained by stone
=
${u}^{2} \div 2g$
Here we will take +g in (2g)
Now
h=
$= {5 }^{2} \div 2 \times 10$
$= 25 \div 20$
$= 12.5 \div 10$
$= 1.25 \: metre$
Now time taken to reach maximum height
$= u \div g$
$= 5 \div 10$
$= 0.5 \: sec$
Time taken to reach the height attained by stone = 0.5 sec.

Height attained by stone= 1.25 metre