Question

a stone is thrown in a vertically upward direction with a velocity of 5 m/s.if the accelaration of the stone during the motion is 10 m/s in the downward direction, what will be the height attained by the stone and how much time will it take to reach there/

Answer 1

h = u^2/2g = 25/2×10 = 5/4 m
u = at
t = a/u = 10/5 = 2sec

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\bold\purple{Answer:-}$

Here, u= 5 m/s

As the acceleration acts in the opposite direction of initial velocity, so it is negative.

a= -10 m/s²

At the highest point, v= 0

Using, v² - u² = 2as, we get

→0² -5² = 2× (-10) × s

→s= 25/20 = 1.25 m

Therefore, the height attained by the stone= 1.25m.

Again,

v= u+at

→0= 5-10×t

or t= 5/10 = 0.5 s

Hence, time taken by the stone to reach the highest point = 0.5 s.

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Hope it helps..:-)

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