A stone is thrown upwards from the surface of the moon with a velocity of 19.6m/s.How much time will it taken to attain the maximum height. How high will it go?
Answers
Answered by
2
~*HEY FRIEND*~
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________
acceleration of moon is 1/4th of the acceleration on earth ...
I.e 9.8/4 m/s^2
initial velocity is given 19.6m/s
final velocity =0
now , time = (v- u )/ a
(0-19.6) / -9.8/4 negative sign due to retardation.
time=8 m/ s
to find distance use formula
s= ut + 1/2 a t^2
= 19.6 +1/2 x 2.45 x 8x8
solve this yiu will get the answer.
HOPE IT WILL HELP YOU
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________
acceleration of moon is 1/4th of the acceleration on earth ...
I.e 9.8/4 m/s^2
initial velocity is given 19.6m/s
final velocity =0
now , time = (v- u )/ a
(0-19.6) / -9.8/4 negative sign due to retardation.
time=8 m/ s
to find distance use formula
s= ut + 1/2 a t^2
= 19.6 +1/2 x 2.45 x 8x8
solve this yiu will get the answer.
HOPE IT WILL HELP YOU
Similar questions