Question

a stone is thrown vertically upward direction with a velocity of 5m/s . if the acceleration of the stone during its motion in 10m/s . in the downward direction , what will be the height attained by the stone and how much time will it take to reach there

Answer 1

$here \: is \: your \: answer$


》Initial velcoity=u=5m/s

》acceleration=10m/s

》time{ t} =?

》Maximum height=h=?

↪using the formula ,

Maximum Height = Hmax

$h_{max} = \frac{ {u}^{2} }{2g}$


=5x5/2x10

=5/4m
=1.25m

↪Time of ascent= Time taken to reach

maximum height=u/g

=5/10
=1/2
=0.5 sec.

$hope \: it \: helps$

$\beta e \: \beta rainly$

Answer 2

》Initial velcoity=u=5m/s

》acceleration=10m/s

》$time{ t}$ =?

》Maximum height=h=?

↪using the formula ,

Maximum Height = Hmax

h_${max} = \frac{ {u}^{2} }{2g}h$

max

=

2g

u

2

=5x5/2x10

=5/4m

=1.25m

↪Time of ascent= Time taken to reach

maximum height=u/g

=5/10

=1/2

=0.5 sec.