Question

A stone is thrown vertically upwards .Find the distance travelled by it in the last second of its upward journey ?​

Answer 1

Given: A stone is thrown vertically upwards.

To find: Distance travelled in last second of its upward journey

Explanation: In the last second of its upward journey, the stone will reach its maximum height. At that point the final velocity of the stone(v) will be zero. Let the speed at starting of the last second of the upward journey be u.

Using kinematics equation:

v= u - gt

=> 0 = u - 10* 1

=> u = 10 m/s

Therefore, the distance covered in the last second of the journey= u^2 / 2g

= 10^2 / 2 * 10

= 100 / 20

= 5 m

Therefore, the distance travelled by it in the last second of its upward journey is 5 m.