A stone is thrown vertically upwards with a speed of 5m/'s.how high does the stone rise before returning back to earth?given acceleration due to earth s attraction g=9.8m per sec square
Answers
Answered by
60
use third equation of motion
s=v²-u²/2a
s =0 -5²/2x9.8
= 0-25/ 19.8
25/19.8
25x10/19.8x 10
250/198
simplify u will get
hope this is correct
s=v²-u²/2a
s =0 -5²/2x9.8
= 0-25/ 19.8
25/19.8
25x10/19.8x 10
250/198
simplify u will get
hope this is correct
Answered by
0
Answer:
it's 250/196
Explanation:
bcz 9.8 ×2×10= 196
Similar questions