Question

a stone is tired to one end of string 50cm long is whirled in a horizontal circle with a constant speed if the stone make 10revolution in 20sec what is the mangnitude of the acceleration of the stone​

Answer 1

Explanation:

Radius =r=50cm=0.5m

In 20 sec revolution =10

In 1 sec revolution =10/20=1/2 Hz

N=1/2Hz

Now,

Angular velocity =W=2πn=w=2×3.14×0.5

Radial Acceleration =w^2r

Radial Acceleration =(3.14)^2×0.5m/s^2

=4.93m/s^2

=493cm/s^2