Question

2)The sum of four of the angles of
a heptagon is 600°. The other three
angles are of sizes 4x°,5xº and
6xº. Find the value of x and hence find
the sizes of the three angles.

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Answer 1

Answer:

Hello mate..

Step-by-step explanation:

Sum of all angles of a quadrilateral is 360

so

4x+5x+10 +7x-20+6x+18=360

22x=352

x=352/22

x=16

each angles are 64 ; 90 ; 92 and 114

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Answer 2

Answer:

heptagon -7 sides=900deg

600°. The other three  angles are of sizes 4x°,5xº and  6xº

900=600+4x+5x+6x

300=15x

20=x

80,100,120 are the angles

Step-by-step explanation: