A stone of mass m is tied to a string and is moved in a vertical circle of radius r having speed v at the lowest point. The tension in the string when the stone is at the lowest point is
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Answer: T = 6mg
V at the lowest point is (5gr)*1/2....(1)
By using
T - mgcostheta = mv*2/r...... (2)
At lowest point angle is 0°
Put (1) in (2)
After solving you will get 6mg
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so according to diagram
T=mg+mv2/r (mv2/r=centrifugal acceleration)
so T=m(g+v2/r)
hope it helps
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