a straight line passes through point (2,5) and has a slope of -3 find the equation of straight line and the value of K if line passes theough point(k,k+3)
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Given :
- A straight line passes through point (2,5) and has a slope of -3.
To find :
- Equation of straight line
- value of K if line passes theough point (k,k+3)
Concept used :
Solution :
Equation of straight line passes through point (2,5) and has a slope of -3 :-
If line passes through point (k,k+3) then put x = k and y = k+3 in y+3x-11=0. Then you can easily find the value of k.
Answer :
- Equation of straight line = y +3x-11=0
- k = 2
Answered by
2
Given ,
A straight line passes through point (2,5) , (k,k+3) and has slope of -3
As we know that , the slope of the line is given by
∴ The equation of the line will be
-3 = (5 - y)/(2 - x)
-6 + 3x = 5 - y
3x + y - 11 = 0
Therefore , the equation of line is 3x + y - 11= 0
Since , (k , k + 3) lies on the line 3x + y - 11 = 0
∴ Put x = k and y = k + 3 in equation of line
3k + (k + 3) - 11 = 0
4k - 8 = 0
4k = 8
k = 2
Therefore , the value of k is 2
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