A straight line passes through the point (2,3) and is such that the sum of it's intercepts on the cordinate axis is 10. find the equation of the straight line
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Answer:
3x+2y=12 ; x+y=5
Step-by-step explanation:
the intercept form of a straight line is x/a+y/b=1
as it is passing through (2,3) we have 2/a+3/b=1; Also sum of intercepts (a+b)=10 (given)
⇒a= 10-b
Substituting the value of 'b' in 2/a+3/b=1 and on solving we get a=4 or 5 for a=4 , b=6 and for a=5 ,b = 5
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solve in the attachment.....
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