Question

find the remainder when x cube - ax square + 6x - a is divided by x-a​

Answer 1

Answer:

p(x)= x³-ax²+6x-a

g(x)= x-a

then x-a = 0

x=a

so.....

p(a)= a³-a*a²+6*a -a

p(a) = a³-a³+6a-a

p(a)= a³-a³+5a

p(a)= 0+5a

p(a)= 5a

thank you

hope it helps

Answer 2

Step-by-step explanation:

hope it will help you ..