A straight rod of length L extends from x = a to x = L + a. The gravitational force it exerts on a point mass ‘m’ at x = 0, if the mass per unit length of the rod is A + Bx², is given by:
(A) Gm[ A{1/(a + L) - 1/a} - BL]
(B) Gm[ A{1/a - 1/(a + L)} - BL]
(C) Gm[ A{1/(a + L) - 1/a} + BL]
(D) Gm[ A{1/a - 1/(a + L)} + BL]
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option d is the answer
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