Physics, asked by Rumaisa6470, 10 months ago

A stream of water flowing horizontally with a speed of 15 m/s

Answers

Answered by Anonymous
1

speed of stream water = 15 m/sec

cross section area of tube = 10^-2 m^2

we know,

volume = cross section area * length of tube

hence,

volume of water coming out per second from the tube = cross section area *speed of stream water

= 10^-2 * 15 = 15* 10^-2 m^3/s

density of water = 10^3 kg/m^3

hence, mass of water coming out per second ( m) = volume per second * density

= 15*10^-2*10^3 kg/s

= 150 kg/s

now,

force exerted on wall by the impact of water = change in linear momentum per second = m* speed of stream water

= 150 * 15 N

= 2250 N

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