A string of length 0.1m cannot bear a tension more than 100N it is tied to a body of mass 10g and rotated in a horizontal circle the maximum angular velocity can be
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When we revolving object with string it moves in circular path hence it has both tangential and centripetal acceleration
centripetal Force is provided by tension in the string.
T = MV²/R
T = MRω²
T = 10×10^-3×1×10^-1 × ω²
100 = 10^-3 × ω
ω² = 100 × 10³
ω² = 10^5
ω = 10²√10
ω = 100√10 rad/s
centripetal Force is provided by tension in the string.
T = MV²/R
T = MRω²
T = 10×10^-3×1×10^-1 × ω²
100 = 10^-3 × ω
ω² = 100 × 10³
ω² = 10^5
ω = 10²√10
ω = 100√10 rad/s
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Please mark it as brainliest.
Answer: 100(10)^1/2
Explanation:
Mass =10gm=0.01kg
R=0.1m
T=mv^2/r-----------(1)
[Since v=ωr]
Putting value in equation 1 we get,
T=m ω^2 R
100=(0.01)ω^2 (0 .1)
100=(0.001)ω^2
100/0.001=ω^2
100000=ω^2
ω=100(10)^1/2
Hope it helps..
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