Question

find HCF of 4052 and 12576 and hence Express it as sum of 4052 and 12576?



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Answer 1

Using Euclid's method
Hence, using the algorithm we have,

12576 = 4052 . 3 + 420

We shall proceed this way until we obtain the remainder as zero.

4052 = 420.9 + 272

420 = 272.1 + 148

272 =148.1 + 124

124 = 4.6 + 0

Hence we have obtained the remainder as zero.

This shows that the H.C.F of 4052 and 12576 is 4.

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